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6x^2+3x^2=90
We move all terms to the left:
6x^2+3x^2-(90)=0
We add all the numbers together, and all the variables
9x^2-90=0
a = 9; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·9·(-90)
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{10}}{2*9}=\frac{0-18\sqrt{10}}{18} =-\frac{18\sqrt{10}}{18} =-\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{10}}{2*9}=\frac{0+18\sqrt{10}}{18} =\frac{18\sqrt{10}}{18} =\sqrt{10} $
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